**Moisture Content Calculator**

Mass of water:

*Mass of solids: *

*Moisture Content***:**

These values are determined by weighing a sample of the soil and then drying the sample in an oven and reweighing. A drying period of 24 hrs at 105-110^{o}C is normally adequate for most soils.

** Degree of Saturation Calculator**

*Volume of water: *

*Volume of voids: *

**Degree of Saturation:**

The degree of saturation can range between the limits of zero for a completely dry soil, and 1 for a fully saturated soil.

**Void Ratio Calculator**

*Volume of voids: *

*Volume of solids: *

**Void Ratio:**

**Porosity Calculator**

*Volume of voids: *

Total volume of media:

**Porosity:**

Example Calculation (Adapted from Craig, 1997)

In it's natural condition a soil sample has a mass of 2290g, a volume of 1.15 x 10^{-3} m^{3}, and particle density of 2540 kg/m^{3 }(density of just the solids). After being completely dried in an oven the mass of the sample is 2035g.

**Moisture Content:**

Mass of water

= 2290-2035 = 225g

Mass of solids

= 2035g

Thus, moisture content = 0.125 or 12.5%

**Degree of Saturation:**

Volume of Water

= mass of water/density of water

= 225g /10^{6} g/m^{3 }= 2.25x10^{-4} m3

**Volume of Voids:**

= total volume - particle volume

= 1.15 x 10-3 m^{3}-(2035g/2.54x10^{6} g/m^{3})

= 1.15 x 10^{-3} m^{3} - 8.01 x 10^{-4} m^{3}

= 3.49 x 10^{-4} m^{3}

Thus, degree of saturation = 0.645 or 64.5%

**Void Ratio:**

Volume of Voids = 3.49 x 10^{-4} m^{3}

Volume of Solids = 8.01 x 10^{-4} m^{3}

Thus, void ratio = 0.44 or 44%

**Porosity:**

Volume of Voids = 3.49 x 10^{-4} m^{3}

Total Volume of Media = 1.15 x 10^{-3} m^{3}

Thus, porosity = 0.303 or 30.3%

References

Craig, R.F. (1997). Soil Mechanics; Sixth Edition. Published by Chapman & Hall, USA.