**
****Moisture
Content
Calculator**

Mass of water:

*Mass of solids: *

*Moisture Content***:**

These values are
determined by weighing a sample of the soil and then drying the
sample in an oven and reweighing. A drying period of 24 hrs
at 105-110^{o}C is normally adequate for most soils.**
**

*
***
Degree of Saturation
Calculator**

*
**Volume of water: *

*Volume of voids:
*

*
*

**Degree of Saturation:**

The degree of saturation
can range between the limits of zero for a completely dry soil,
and 1 for a fully saturated soil.**
**

**Void
Ratio Calculator**

*
**Volume of voids: *

*Volume of solids:
*

*
*

**Void Ratio:**

**Porosity
Calculator**

*Volume of voids: *

Total volume of media:

**Porosity:**

Example
Calculation (Adapted from Craig, 1997)

In it's natural condition a soil sample has a
mass of 2290g, a volume of 1.15 x 10^{-3} m^{3},
and particle density of 2540 kg/m^{3 }(density of just the
solids). After being completely dried in an oven the mass of
the sample is 2035g.

**Moisture Content:**

Mass of water

= 2290-2035 = 225g

Mass of solids

= 2035g

Thus, moisture content = 0.125 or 12.5%

**Degree of Saturation:**

Volume of Water

= mass of water/density of
water

= 225g /10^{6}
g/m^{3 }= 2.25x10^{-4} m3

**Volume of Voids:**

= total volume - particle volume

= 1.15 x 10-3 m^{3}-(2035g/2.54x10^{6}
g/m^{3})

= 1.15 x 10^{-3} m^{3}
- 8.01 x 10^{-4} m^{3}

= 3.49 x 10^{-4} m^{3}

Thus, degree of saturation = 0.645 or 64.5%

**Void Ratio:**

Volume of Voids = 3.49 x 10^{-4} m^{3}

Volume of Solids = 8.01 x 10^{-4} m^{3}

Thus, void ratio = 0.44 or 44%

**Porosity:**

Volume of Voids = 3.49 x 10^{-4} m^{3}

Total Volume of Media = 1.15 x 10^{-3}
m^{3}

Thus,
porosity = 0.303 or 30.3%**
**

* *

References

Craig, R.F. (1997).
Soil
Mechanics; Sixth Edition. Published by Chapman & Hall,
USA.**
**

* *

Click here to see
all equations
used